A mixed strategy assigns probabilities to a player’s pure strategies. It is a mathematical description of a choice distribution, not an instruction for wagering or a guarantee about an individual result. This guide uses two abstract labels to show how mixed strategies can form an equilibrium when no pure action profile does.
Define a distribution over the available actions
Two players each choose A or B simultaneously. Row receives one utility unit if the labels match and minus one if they differ; Column receives the opposite value. The Yale lecture defining mixed strategies explains that probabilities are nonnegative and sum to one. Let p be Row’s probability of A and q Column’s probability of A. Their probabilities of B are 1−p and 1−q. The utility units here are invented, with no monetary stakes or real-world performance interpretation.
Check why no pure profile is stable
If both choose the same label, Column prefers switching to create a mismatch. If they choose different labels, Row prefers switching to create a match. Thus every pure action pair offers one player an improving unilateral deviation. This exhausts the four possibilities, establishing that this particular game has no pure Nash equilibrium. It does not establish the absence of an equilibrium once probability distributions are available. Enlarging the strategy space changes what must be checked, while preserving the same underlying payoff table.
Calculate joint probabilities under independent mixing
| Row label | Column label | Joint probability | Payoffs (Row, Column) |
|---|---|---|---|
| A | A | 1/4 | (1, −1) |
| A | B | 1/4 | (−1, 1) |
| B | A | 1/4 | (−1, 1) |
| B | B | 1/4 | (1, −1) |
The four probabilities sum to one. Row’s expected payoff is 1/4−1/4−1/4+1/4=0, and Column’s is also zero. Each realised payoff is still either one or minus one. An expected value of zero describes the probability-weighted average, not a fifth terminal outcome in which both players necessarily receive zero.
Use indifference to identify the candidate mix
Against Column’s probability q of A, Row’s expected utility from pure A is q−(1−q)=2q−1. From pure B it is (1−q)−q=1−2q. These are equal when q=1/2. Similarly, Column is indifferent between its two labels when p=1/2. At p=q=1/2 neither player can improve by changing their own distribution while the other distribution remains fixed. Because every mixture is a weighted average of the two pure-action expected utilities, equal zero values rule out any profitable unilateral mixture in this abstract model.
Know what the support condition requires
In Nash’s original equilibrium formulation, strategies used with positive probability at equilibrium must be best responses to the others. This is stronger than merely making some chosen actions equal in value. If an omitted third action gave a higher expected payoff, a mixture over two equally valued but inferior actions would not be a best response. Check both indifference within the positive-probability support and the absence of a better action outside it. A pure strategy is included as the special case assigning probability one to one action.
Distinguish probability from a visible schedule
Choosing A and B on a known alternating schedule can produce a fifty-fifty frequency over an even number of rounds, but it is not the same information structure as independent random choices. An opponent who observes the schedule can condition on the next label. Likewise, two players following a shared random signal can have correlated choices even if each marginal distribution is half A and half B. Marginal frequencies alone do not establish the four equal joint probabilities in the table. State the randomisation and information assumptions explicitly.
Keep formal equilibrium separate from observed behaviour
The Manchester course notes on game models distinguish mathematical representations and the reasoning applied to them. A mixed equilibrium is a property of specified utilities and available choices. It does not prove that people implement exact probabilities, that a short observed sequence matches theoretical frequencies or that every strategic interaction should be randomised. Empirical evaluation would require observations and a design appropriate to the question. The abstract calculation here establishes a model result while leaving those behavioural questions open.
Mixed-strategy calculation checklist
- Specify pure actions and all payoff pairs.
- Define probabilities that are nonnegative and sum to one.
- State whether players’ random choices are independent.
- Calculate expected utility for every pure action.
- Check supported actions are equally best, not merely equal.
- Test omitted actions and unilateral changes.
- Separate expected values from individual outcomes and observed frequencies.
The matching example is useful because every calculation fits in a small table. Retaining the general symbols p and q before substituting one half makes the logic inspectable: each player’s indifference is determined by the other player’s mixture. That distinction prevents a common error in which a player’s own probabilities are used to equalise the wrong payoff expressions.
Frequently asked questions
Must a mixed strategy use every pure action?
No. It can assign zero probability to some actions; only positive-probability actions belong to its support.
Is a fifty-fifty observed frequency enough to prove independent randomisation?
No. Deterministic schedules or correlated signals can have those marginal frequencies while producing different conditional or joint probabilities.
Does expected utility zero mean every realised payoff is zero?
No. In the hypothetical model each realised payoff is one or minus one, while their probability-weighted average is zero.
Sources and verification
- Game Theory, Lecture 9: mixed strategies — Open Yale Courses — 2026-10-23
- Non-Cooperative Games, doctoral dissertation, 1950 — John Nash; Princeton University Library archive — 2026-10-23
- Games, Games, Games: notes for the game theory course — Andrea Schalk, University of Manchester — 2026-10-23